\sqrt[3]{(64/343)}=?
a) 4/9
b) 4/7
c) 8/7
d) 8/21
Firstly we have to find the prime factors of 64
64 = 2 × 2 × 2 × 2 × 2 × 2
And the prime factors of 343
343 = 7 × 7 × 7
\sqrt[3]{(64/343)}=\sqrt[3]{(4\times4\times4/4\times4\times4)}
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