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A bag contains 5 white, 6 red, and 4 green balls. One ball is drawn at random.

What is the probability that the ball drawn is (i) green? (ii) White? (iii) Nonred?

Answer:

i. We know that the bag containing the total balls = 5white+6red+4green =

15balls

Green balls = 4

By using the formula,

Probability p () = number of favorable outcomes/ total number of outcomes

∴ Probability of getting a green ball p (G) = number of green balls/total number of balls

=4/15

ii. We know that the bag containing the total balls = 5white +6red+4green =

15balls

White balls = 5

By using the formula,

Probability p () = number of favorable outcomes/ total number of outcomes

∴ Probability of getting a white ball p (W) = number of white balls/total number of balls

=5/15=1/3

iii. We know that the bag containing the total balls = 4white +6red+4green =

15balls

Number of outcomes (excluding red) = 5white+4green=9balls

By using the formula,

Probability p () = number of favorable outcomes/ total number of outcomes

∴ Probability of getting a green ball p (G) = number of white balls/total number of balls

=9/15=3/5

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