A bag contains 5 white, 6 red, and 4 green balls. One ball is drawn at random.
What is the probability that the ball drawn is (i) green? (ii) White? (iii) Nonred?
i. We know that the bag containing the total balls = 5white+6red+4green =
15balls
Green balls = 4
By using the formula,
Probability p () = number of favorable outcomes/ total number of outcomes
∴ Probability of getting a green ball p (G) = number of green balls/total number of balls
=4/15
ii. We know that the bag containing the total balls = 5white +6red+4green =
15balls
White balls = 5
By using the formula,
Probability p () = number of favorable outcomes/ total number of outcomes
∴ Probability of getting a white ball p (W) = number of white balls/total number of balls
=5/15=1/3
iii. We know that the bag containing the total balls = 4white +6red+4green =
15balls
Number of outcomes (excluding red) = 5white+4green=9balls
By using the formula,
Probability p () = number of favorable outcomes/ total number of outcomes
∴ Probability of getting a green ball p (G) = number of white balls/total number of balls
=9/15=3/5
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