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Ml aggarwal solutions

CHAPTERS

**A father is 7 times as old as his son. Two years ago, the father was 13 times as old as his son. How old are they now?**

Let the present age of son be x years

Then, age of his father will be 7x years

Two years ago, age of son = (x – 2) years

Two years ago, age of his father = (7x – 2) years

According to the given problem,

7x – 2 = 13 (x – 2)

7x – 2 = 13x – 26

7x – 13x = - 26 + 2

-6x = - 24

x = - 24 /- 6

We get,

x = 4

Therefore, age of son = 4 years and

Age of his father = 7x = 7 × 4 = 28 years

Let the present age of son be x years

Then, age of his father will be 7x years

Two years ago, age of son = (x – 2) years

Two years ago, age of his father = (7x – 2) years

According to the given problem,

7x – 2 = 13 (x – 2)

7x – 2 = 13x – 26

7x – 13x = - 26 + 2

-6x = - 24

x = - 24 /- 6

We get,

x = 4

Therefore, age of son = 4 years and

Age of his father = 7x = 7 × 4 = 28 years

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