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Rs aggarwal solutions
Grade 8 
Mathematics
Mathematics class 8th RS Aggarwal
Volume and Surface Area of Solids
Volume and Surface Area of Solids Exercise 20A
Question 3
Mathematics
Mathematics class 8th RS Aggarwal
Volume and Surface Area of Solids
Volume and Surface Area of Solids Exercise 20A
Question 3
Volume and Surface Area of Solids | Volume and Surface Area of Solids Exercise 20A
Question 3
A cardboard box is 1.2m long, 72cm wide, and 54cm high. How many bars of soap
can be put it into it if each bar measures 6cm × 4.5 cm × 4 cm?
We know that volume of cuboid = length × breadth × height
V = 120 × 72 × 54 = 466560 cm3
Volume of each bar soap = 6 × 4.5 × 4 = 108 cm3
Therefore, total number of soaps can be accommodated in a box is
Volume of the box/ volume of each soap
= 466560/108
= 4320 bars
Question 3
A cardboard box is 1.2m long, 72cm wide, and 54cm high. How many bars of soap
can be put it into it if each bar measures 6cm × 4.5 cm × 4 cm?
We know that volume of cuboid = length × breadth × height
V = 120 × 72 × 54 = 466560 cm3
Volume of each bar soap = 6 × 4.5 × 4 = 108 cm3
Therefore, total number of soaps can be accommodated in a box is
Volume of the box/ volume of each soap
= 466560/108
= 4320 bars
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