Rs aggarwal solutions
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Volume and Surface Area of Solids | Volume and Surface Area of Solids Exercise 20A

Question 3

A cardboard box is 1.2m long, 72cm wide, and 54cm high. How many bars of soap

can be put it into it if each bar measures 6cm × 4.5 cm × 4 cm?

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We know that volume of cuboid = length × breadth × height

V = 120 × 72 × 54 = 466560 cm3

Volume of each bar soap = 6 × 4.5 × 4 = 108 cm3

Therefore, total number of soaps can be accommodated in a box is

Volume of the box/ volume of each soap

= 466560/108

= 4320 bars

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Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 3

A cardboard box is 1.2m long, 72cm wide, and 54cm high. How many bars of soap

can be put it into it if each bar measures 6cm × 4.5 cm × 4 cm?

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

We know that volume of cuboid = length × breadth × height

V = 120 × 72 × 54 = 466560 cm3

Volume of each bar soap = 6 × 4.5 × 4 = 108 cm3

Therefore, total number of soaps can be accommodated in a box is

Volume of the box/ volume of each soap

= 466560/108

= 4320 bars

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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