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A can do a job in 16 days and B can do the same job in 12 days. With the help

of C. they can finish the job in 6 days only. Then, C alone can finish it in

a) 34 da

b) 22 days

c) 36 days

d) 48 days

Answer:

we know that,

Number of hours A required to do a piece of work = 16 days

Number of hour B required to do a piece of work = 12 days

Let us consider the number of days C required to do a piece of work = x days

Number of hours A, B, and C together required to do a piece of work = 6 days

∴ We can calculate, work done by A in 1 day = 1/16

Work is done by B in 1 day = 1/12

Work is done by C in 1 day = 1/x

Work is done by A, B, and C together in a 1 day = 1/6

Now, work done by A,B and C together in 1 day = 1/16 + 1/12 +1/x = 7/48 + 1/x

7/48 + 1/x = 1/6

(7x+48)/48x = 1/6

42x + 288 = 48x

6x = 288

x = 288/6 = 48

∴ C can do the work in 48 days.

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