A can do a job in 16 days and B can do the same job in 12 days. With the help
of C. they can finish the job in 6 days only. Then, C alone can finish it in
a) 34 da
b) 22 days
c) 36 days
d) 48 days
we know that,
Number of hours A required to do a piece of work = 16 days
Number of hour B required to do a piece of work = 12 days
Let us consider the number of days C required to do a piece of work = x days
Number of hours A, B, and C together required to do a piece of work = 6 days
∴ We can calculate, work done by A in 1 day = 1/16
Work is done by B in 1 day = 1/12
Work is done by C in 1 day = 1/x
Work is done by A, B, and C together in a 1 day = 1/6
Now, work done by A,B and C together in 1 day = 1/16 + 1/12 +1/x = 7/48 + 1/x
7/48 + 1/x = 1/6
(7x+48)/48x = 1/6
42x + 288 = 48x
6x = 288
x = 288/6 = 48
∴ C can do the work in 48 days.
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