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A and B, working together can finish a piece of work in 6 days, while A alone

can do it in 9 days. How much time will B alone take to finish it?

Answer:

we know that,

Number of days A required to do a piece of work = 9 days

Let us consider a number of days B required to do a piece of work = X days

Number of hours required by A and B together to do a piece of work = 6 days

∴ We can calculate, work done by A in 1 day = 1/9

Work is done by B in 1 day = 1/x

Work is done by both A and B in a day = 1/6

Work done by both A and B in 1 day= 1/9 + 1/x = x+9/9x

x+9/9x = 1/6

6x + 54 = 9x

3x = 54

x = 54/3

x = 18

∴ B can do the work in 18 days

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