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(2/3) of a number is less than the original number by 20. Find the number.

Answer:

Solution:-

Let the required number be x.

Then,

= (2x/3) = x – 20

Transposing x to LHS and it becomes –x.

= (2x/3) – x = -20

= (2x – 3x)/3 = -20

= -x/3 = -20

Multiplying both side by - 3

= (-x/3) × -3 = -20 × -3

= x = 60

∴ the required number is 60

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