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RS Aggarwal Solutions Class 7 Mathematics Solutions for Linear Equations in one variable Exercise 7B in Chapter 7 - Linear Equations in one variable
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The fifth part of a number when increased by 5 equals its fourth part decreased by 5. Find the
number.
Answer:
Solution:-
Let the required number be x.
Then,
= (x/5) + 5 = (x/4) – 5
Transposing (x/4) to LHS and it becomes – (x/4) and 5 to RHS it becomes -5
= (x/5) – (x/4) = -5 - 5
= (4x – 5x)/20 = -10
= -x/20 = -10
Multiplying both side by (-20)
= (-x/20) × (-20) = (-10) × (-20)
= x = 200
∴the required numbers are 200
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