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Mensuration | Mensuration Exercise 20B

Question 2

A rectangular grassy lawn measuring 38 m by 25 m has been surrounded externally by a 2.5-m wide path. Calculate the cost of graveling the path at the rate of ₹ 120 per\mathrm{m}^{2}.

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From the question,

Length EF = 38 m

Breadth FG = 25 m

Area of the plot EFGH = (38 × 25)\mathrm{m}^{2}

=950 \mathrm{m}^{2}

Width of the path = 2.5 m

∴AB = (38 + (2 × 2.5)) = (38 + (5)) = 43 m

and BC = (25 + (2 × 2.5)) = (25 + (5)) = 30 m

Area of the rect. ABCD = (43 × 30)\mathrm{m}^{2}

=1290 \mathrm{m}^{2}

Area of the path = ( area ABCD) – (area EFGH)

= (1290 – 950)

=340 \mathrm{m}^{2}

Rate of gravelling the path = ₹ 120 per \mathrm{m}^{2}

∴Total cost of gravelling the path = ₹ (120 × 340)

= ₹ 40800

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Question 2

A rectangular grassy lawn measuring 38 m by 25 m has been surrounded externally by a 2.5-m wide path. Calculate the cost of graveling the path at the rate of ₹ 120 per\mathrm{m}^{2}.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

From the question,

Length EF = 38 m

Breadth FG = 25 m

Area of the plot EFGH = (38 × 25)\mathrm{m}^{2}

=950 \mathrm{m}^{2}

Width of the path = 2.5 m

∴AB = (38 + (2 × 2.5)) = (38 + (5)) = 43 m

and BC = (25 + (2 × 2.5)) = (25 + (5)) = 30 m

Area of the rect. ABCD = (43 × 30)\mathrm{m}^{2}

=1290 \mathrm{m}^{2}

Area of the path = ( area ABCD) – (area EFGH)

= (1290 – 950)

=340 \mathrm{m}^{2}

Rate of gravelling the path = ₹ 120 per \mathrm{m}^{2}

∴Total cost of gravelling the path = ₹ (120 × 340)

= ₹ 40800

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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