RS Aggarwal Solutions Class 7 Mathematics Solutions for Fractions Exercise 2B in Chapter 2 - Fractions

Question 14 Fractions Exercise 2B

[1(4/7)] × [1(13/22)] × [1(1/15)]

Answer:

Solution:-

By the rule Multiplication of fraction,

Product of fraction = (product of numerator)/ (product of denominator)

Then,

By Converting mixed fraction into an improper fraction we get,

= (11/7) × (35/22) × (16/15)

= (11×35×16)/ (7×22×15)

On simplifying we get,

= (1×5×16) / (1×2×15)

Again simplifying we get,

= (1×1×8)/ (1×1×3)

= (8/3)

= [2(2/3)]

Related Questions

Find the product: [5(5/6)] × [1(5/7)]

Find the product:(3/5) × (7/11)

Find the product: [3(1/8)] × (16)

Find the product: [4(1/8)] × [2(10/11)]

Find the product: (2/5) × 15

Find the product: (4/9) × (15/16)

Was This helpful?

Exercises

Fractions Exercise 2A

Fractions Exercise 2B

Fractions Exercise 2C

Fractions Exercise 2D

Chapters

Integers

Fractions

Decimals

Rational Numbers

Exponents

Algebraic Expressions

Linear Equations in one variable

Ratio and Proportion

Unitary Method

Percentage

Profit and Loss

Simple Interest

Lines and Angles

Properties of Parallel Line

Properties of Triangles

Congruence

Constructions

Reflection and Rotational Symmetry

Three-Dimensional Shapes

Mensuration

Collection and Organisation of Data (Mean, Median, Mode)

Bar Graphs

Probability