Find the complement of each of the following angles:
(i). 35^{\circ}
(ii) 47^{\circ}
(iii) 60^{\circ}
(iv) 73^{0}
(i) Two angles are said to be complementary if the sum of their measures is 90^{\circ}.
The given angle is 35^{\circ}.
Let the measure of its complement be x^{\circ}.
Then,
= x + 35 = 90
= x = 90 – 35
= x = 55^{\circ}
Hence, the complement of the given angle measures 55^{\circ}.
(ii) Two angles are said to be complementary if the sum of their measures is 90^{\circ}.
The given angle is 47^{\circ}
Let the measure of its complement be x^{\circ}.
Then,
= x + 47 = 90
= x = 90 – 47
= x = 43^{\circ}
Hence, the complement of the given angle measures 43^{\circ}.
(iii) Two angles are said to be complementary if the sum of their measures is 90^{\circ}.
The given angle is 60^{\circ}.
Let the measure of its complement be x^{\circ}.
Then,
= x + 60 = 90
= x = 90 – 60
= x = 30^{\circ}.
Hence, the complement of the given angle measures 30^{\circ}.
(iv) Two angles are said to be complementary if the sum of their measures is 90^{\circ}.
The given angle is 73^{\circ}
Let the measure of its complement be x^{0}.
Then,
= x + 73 = 90
= x = 90 – 73
= x = 17^{\circ}
Hence, the complement of the given angle measures 17^{\circ}.
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