Rs aggarwal solutions
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Percentage | Percentage Exercise 10B

Question 7

36 % of the maximum marks are required to pass a test. A student gets 123 marks and is declared

fail by 39 marks. Find the maximum marks.

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Solution:-

Let the x be the maximum marks,

Passing marks for the test = (123 + 39) = 162

Then, 36% of x = 162

= (36/100) × x = 162

= x = (162 × 100) / 36

= x = 450

∴the maximum marks is 450.

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Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 7

36 % of the maximum marks are required to pass a test. A student gets 123 marks and is declared

fail by 39 marks. Find the maximum marks.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Solution:-

Let the x be the maximum marks,

Passing marks for the test = (123 + 39) = 162

Then, 36% of x = 162

= (36/100) × x = 162

= x = (162 × 100) / 36

= x = 450

∴the maximum marks is 450.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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