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Rs aggarwal solutions
Percentage | Percentage Exercise 10B
Question 7
36 % of the maximum marks are required to pass a test. A student gets 123 marks and is declared
fail by 39 marks. Find the maximum marks.
Solution:-
Let the x be the maximum marks,
Passing marks for the test = (123 + 39) = 162
Then, 36% of x = 162
= (36/100) × x = 162
= x = (162 × 100) / 36
= x = 450
∴the maximum marks is 450.
Question 7
36 % of the maximum marks are required to pass a test. A student gets 123 marks and is declared
fail by 39 marks. Find the maximum marks.
Solution:-
Let the x be the maximum marks,
Passing marks for the test = (123 + 39) = 162
Then, 36% of x = 162
= (36/100) × x = 162
= x = (162 × 100) / 36
= x = 450
∴the maximum marks is 450.
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