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Rs aggarwal solutions
Integers | Integers Exercise 1B
Question 29
10 × (-12) + 5 × (-12)
Solution:-
Using the Distributive Law of Multiplication [(a×c) + (b×c) = (a + b) ×c)]
Let,
a= 10, b= 5, c= -12
Then,
=10 × (-12) + 5 × (-12)
The above equation can be written as,
= {(10+5) × (-12)} … [∵(a×c) + (b×c) = (a + b) ×c)]
= {(15) × (-12)} … [∵ (+ × −= −)]
= -180
Question 29
10 × (-12) + 5 × (-12)
Solution:-
Using the Distributive Law of Multiplication [(a×c) + (b×c) = (a + b) ×c)]
Let,
a= 10, b= 5, c= -12
Then,
=10 × (-12) + 5 × (-12)
The above equation can be written as,
= {(10+5) × (-12)} … [∵(a×c) + (b×c) = (a + b) ×c)]
= {(15) × (-12)} … [∵ (+ × −= −)]
= -180
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