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Rs aggarwal solutions
Integers | Integers Exercise 1B
Question 33
(-11) × (-15)+ (-11) ×(-25)
Solution:-
Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]
Let,
a= -11, b= -15, c= -25
Then,
= (-11) × (-15) + (-11) ×(-25)
The above equation can be written as,
= (-11) × {(-15) + (-25)} … [∵(a×b) + (a×c) = a ×(b+c)]
= (-11) × {-15-25} … [∵ (+ × −= −)]
= (-11) × (-40) … [∵(− × −= +)]
= 440
Question 33
(-11) × (-15)+ (-11) ×(-25)
Solution:-
Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]
Let,
a= -11, b= -15, c= -25
Then,
= (-11) × (-15) + (-11) ×(-25)
The above equation can be written as,
= (-11) × {(-15) + (-25)} … [∵(a×b) + (a×c) = a ×(b+c)]
= (-11) × {-15-25} … [∵ (+ × −= −)]
= (-11) × (-40) … [∵(− × −= +)]
= 440
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