chapter-header

RS Aggarwal Solutions Class 7 Mathematics Solutions for Integers Exercise 1B in Chapter 1 - Integers

Question 28 Integers Exercise 1B

(-16) × (-15) + (-16) × (-5)

Answer:

Solution:-

Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]

Let,

a= -16, b= -15, c= -5

Then,

(-16) × (-15) + (-16) × (-5)

The above equation can be written as,

= (-16) × {(-15) + (-5)} … [∵(a×b) + (a×c) = a ×(b+c)]

= (-16) × {(-15- 5)} … [∵ (+ × −= −)]

= (-16) × {-20} … [∵(− × −= +)]

= 320

Connect with us on social media!
2022 © Quality Tutorials Pvt Ltd All rights reserved