RS Aggarwal Solutions Class 7 Mathematics Solutions for Integers Exercise 1B in Chapter 1 - Integers

Question 31 Integers Exercise 1B

20 × (-16) + 20 × 14

Answer:

Solution:-

Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]

Let,

a=20, b=-16, c= 14

Then,

= 20 × (-16) + 20 × 14

The above equation can be written as,

= 20 × {(-16) + 14} … [∵(a×b) + (a×c) = a ×(b+c)]

= 20 × {-2} … [∵ (+ × −= −)]

= -40

Related Questions

Multiply: -35 by 0

Multiply: – 28 by 14

Multiply: 36 by -11

Multiply: -105 by -8

Multiply: – 53 by 18

Multiply: 18 by -6

Exercises

Integers Exercise 1A

Integers Exercise 1B

Integers Exercise 1C

Integers Exercise 1D

Chapters

Integers

Fractions

Decimals

Rational Numbers

Exponents

Algebraic Expressions

Linear Equations in one variable

Ratio and Proportion

Unitary Method

Percentage

Profit and Loss

Simple Interest

Lines and Angles

Properties of Parallel Line

Properties of Triangles

Congruence

Constructions

Reflection and Rotational Symmetry

Three-Dimensional Shapes

Mensuration

Collection and Organisation of Data (Mean, Median, Mode)

Bar Graphs

Probability