Our top 5% students will be awarded a special scholarship to Lido.
Rs aggarwal solutions
Integers | Integers Exercise 1B
Question 31
20 × (-16) + 20 × 14
Solution:-
Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]
Let,
a=20, b=-16, c= 14
Then,
= 20 × (-16) + 20 × 14
The above equation can be written as,
= 20 × {(-16) + 14} … [∵(a×b) + (a×c) = a ×(b+c)]
= 20 × {-2} … [∵ (+ × −= −)]
= -40
Question 31
20 × (-16) + 20 × 14
Solution:-
Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]
Let,
a=20, b=-16, c= 14
Then,
= 20 × (-16) + 20 × 14
The above equation can be written as,
= 20 × {(-16) + 14} … [∵(a×b) + (a×c) = a ×(b+c)]
= 20 × {-2} … [∵ (+ × −= −)]
= -40
Lido
Courses
Quick Links
Terms & Policies
Terms & Policies
Connect with us on social media!
2021 © Quality Tutorials Pvt Ltd All rights reserved