20 × (-16) + 20 × 14
Solution:-
Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]
Let,
a=20, b=-16, c= 14
Then,
= 20 × (-16) + 20 × 14
The above equation can be written as,
= 20 × {(-16) + 14} … [∵(a×b) + (a×c) = a ×(b+c)]
= 20 × {-2} … [∵ (+ × −= −)]
= -40
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