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RS Aggarwal Solutions Class 7 Mathematics Solutions for Integers Exercise 1B in Chapter 1 - Integers

Question 31 Integers Exercise 1B

20 × (-16) + 20 × 14

Answer:

Solution:-

Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]

Let,

a=20, b=-16, c= 14

Then,

= 20 × (-16) + 20 × 14

The above equation can be written as,

= 20 × {(-16) + 14} … [∵(a×b) + (a×c) = a ×(b+c)]

= 20 × {-2} … [∵ (+ × −= −)]

= -40

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