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RS Aggarwal Solutions Class 7 Mathematics Solutions for Integers Exercise 1B in Chapter 1 - Integers

Question 30 Integers Exercise 1B

(-8) ×9 + (-8) ×7

Answer:

Solution:-

Using the Distributive Law of Multiplication [(a×b) + (a×c) = a ×(b+c)]

Let,

a = -8, b = 9, c = 7

Then,

= (-8) ×9 + (-8) ×7

The above equation can be written as,

= (-8) ×(9+7) … [∵(a×b) + (a×c) = a ×(b+c)]

= (-8) ×(16) … [∵ ( − × += −]

= -128

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