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RS Aggarwal Solutions Class 6 Mathematics Solutions for Whole Numbers Exercise 3F in Chapter 3 - Whole Numbers

Question 11 Whole Numbers Exercise 3F

587 × 99 =?

(a) 57213

(b) 58513

(c) 58113

(d) 56413

Answer:

By using distributive law of multiplication over subtraction we get

587 × 99 = 587 × (100 – 1)

= 587 × 100 – 587 × 1

= 58700 – 587

= 58113

Option (c) is the correct answer

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