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RS Aggarwal Solutions Class 6 Mathematics Solutions for Factors and Multiples Exercise 2F in Chapter 2 - Factors and Multiples

Question 15 Factors and Multiples Exercise 2F

289/391 when reduced to the lowest terms is

(a) 11/23

(b) 13/31

(c) 17/ 31

(d) 17/23

Answer:

Dividing both numerator and denominator by the HCF of 289/391

R S Aggarwal Solutions - Mathematics - Class 6 chapter Factors and Multiples Question 15 Solution image

Hence 289/391 = 17/23

17/23 is the correct answer

Option (d) is the correct answer

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