RS Aggarwal Solutions Class 6 Mathematics Solutions for Factors and Multiples Exercise 2E in Chapter 2 - Factors and Multiples

Question 12 Factors and Multiples Exercise 2E

Find the HCF and LCM of

145,232

Answer:

To find the HCF of 232 and 145

R S Aggarwal Solutions - Mathematics - Class 6 chapter Factors and Multiples Question 12 Solution image

∴ HCF of 145 and 232 = 29

Since, LCM = product of numbers / HCF

= 145 × 232 / 29

= 5 × 232

= 1160

∴ LCM = 1160 and HCF = 29

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Exercises

Factors and Multiples Exercise 2A

Factors and Multiples Exercise 2B

Factors and Multiples Exercise 2C

Factors and Multiples Exercise 2D

Factors and Multiples Exercise 2E

Factors and Multiples Exercise 2F

Chapters

Number System

Factors and Multiples

Whole Numbers

Integers

Fractions

Simplification

Decimals

Algebraic Expressions

Linear Equations in One Variable

Ratio, Proportion and Unitary Method.

Line Segment, Ray and Line

Parallel Lines

Angles and Their Measurement

Constructions (Using a Ruler and a pair of Compasses)

Triangles

Quadrilaterals

Circles

Three – Dimensional Shapes

Two-Dimensional Reflection Symmetry (Linear Symmetry)

Concept of Perimeter and Area

Data Handling

Pictograph

Bar Graph