Jump to

- Real Numbers
- Linear Equations In Two Variables
- Coordinate Geometry
- Triangles
- Circles
- Constructions
- Trigonometric Ratios
- T-Ratios Of Some Particular Angles
- Trigonometric Ratios Of Complementary Angles
- Trigonometric Identities
- Height And Distance
- Perimeter And Area Of Plane Figures
- Area Of Circle Sector And Segment

3: Construct a ∆PQR, in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then, construct another a triangle whose sides are 4/5 times the corresponding sides of ∆PQR.

Answer:

Steps of construction:

- Draw a line segment PQ = 6 cm.
- Draw an arc, using P as a center and radius = 8 cm
- Draw another arc, using Q as a center and radius = 7 cm
- Now, join PR and QR to get △PQR
- Draw a ray PX by making an acute angle, angle QPX
- Divide PX into 4 equal parts 7.
- Join P5Q
- Draw a line P4Q' which is parallel to P5Q
- Similar to step 8, draw a line Q’R’ which is parallel to QR
- Therefore, △PQ’R’ is the required triangle.

Related Questions

Was This helpful?

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved