3 Construct a PQR in which PQ 6 cm QR 7 cm and PR 8 cm Then construct another a triangle whose sides...

Question

3 Construct a PQR in which PQ 6 cm QR 7 cm and PR 8 cm Then construct another a triangle whose sides are 45 times the corresponding sides of PQR

Accepted Answer

Steps of construction 1 Draw a line segment PQ 6 cm 2 Draw an arc using P as a center and radius 8 cm 3 Draw another arc using Q as a center and radius 7 cm 4 Now join PR and QR to get PQR 5 Draw a ray PX by making an acute angle angle QPX 6 Divide PX into 4 equal parts 7 7 Join P5Q 8 Draw a line P4Q which is parallel to P5Q 9 Similar to step 8 draw a line QR which is parallel to QR 10 Therefore PQR is the required triangle

RS Aggarwal Solutions Class 10 Mathematics Solutions for Constructions Exercise 9A in Chapter 9 - Constructions