Rs aggarwal solutions
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Constructions | Constructions Exercise 9A

Question 3

3: Construct a ∆PQR, in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then, construct another a triangle whose sides are 4/5 times the corresponding sides of ∆PQR.

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Steps of construction:

  1. Draw a line segment PQ = 6 cm.
  2. Draw an arc, using P as a center and radius = 8 cm
  3. Draw another arc, using Q as a center and radius = 7 cm
  4. Now, join PR and QR to get △PQR
  5. Draw a ray PX by making an acute angle, angle QPX
  6. Divide PX into 4 equal parts 7.
  7. Join P5Q
  8. Draw a line P4Q' which is parallel to P5Q
  9. Similar to step 8, draw a line Q’R’ which is parallel to QR
  10. Therefore, △PQ’R’ is the required triangle.
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subject-cta

Question 3

3: Construct a ∆PQR, in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then, construct another a triangle whose sides are 4/5 times the corresponding sides of ∆PQR.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Steps of construction:

  1. Draw a line segment PQ = 6 cm.
  2. Draw an arc, using P as a center and radius = 8 cm
  3. Draw another arc, using Q as a center and radius = 7 cm
  4. Now, join PR and QR to get △PQR
  5. Draw a ray PX by making an acute angle, angle QPX
  6. Divide PX into 4 equal parts 7.
  7. Join P5Q
  8. Draw a line P4Q' which is parallel to P5Q
  9. Similar to step 8, draw a line Q’R’ which is parallel to QR
  10. Therefore, △PQ’R’ is the required triangle.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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