# RS Aggarwal Solutions Class 10 Mathematics Solutions for Area Of Circle Sector And Segment Exercise 16A in Chapter 16 - Area Of Circle Sector And Segment

Question 4 Area Of Circle Sector And Segment Exercise 16A

A copper wire when bent in the form of a square encloses an area of 484 cm^2. The same wire is not bent in the form of a circle. Find the area enclosed by the circle.

Let the square be of side ‘a’ cm and radius of the circle be ‘r’

The area enclosed by the square = 484 cm^2

Also, we know that Area of square = Side × Side

Area of the square = a^2

=> a^2 = 484

=> a = √484

=> a = 22

Therefore, the side of the square is 22 cm.

Perimeter of square = 4 x side = 4 x 22 = 88

From the statement, the circumference of the circle = Perimeter of a square

2πr = 88

r = (88 x 7)/(2x22) = 14

The radius of the circle = 14 cm

Area of circle = πr^2 = 22/7 x 14 x 14 = 616 cm^2.

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