RS Aggarwal Solutions Class 10 Mathematics Solutions for Area Of Circle Sector And Segment Exercise 16A in Chapter 16 - Area Of Circle Sector And Segment
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A chord of a circle of radius 30 cm makes an angle of 60^0 at the centre of the circle. Find the areas of the minor-major segments. (take pi = 3.14 and √3 = 1.7)
Radius of circle = r = 30 cm
Area of minor segment = Area of the sector – Area of the triangle ...(1)
Area of major segment = Area of the circle – the area of the minor segment ...(2)
Area of sector = θ/360 x πr^2
= 60/360 x 3.14 x 30 x 30
= 471 cm^2
Area of triangle = √3/4 (side)^2 (Since it forms an equilateral triangle)
= √3/4 x 30 x 30
= 389.7 cm^2
(1) =>
Area of minor segment = 471 – 389.7 = 81.3 cm^2
(2) =>
Area of major segment = π(30^2) – 81.3 = 2744.7 cm^2
Area of the major segment is 2744.7 cm^2 and of the minor segment is 81.3 cm^2.
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