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# Question 1

1500 families with 2 children were selected randomly, and the following data were recorded:

no. of girls in a family 0 1 2
no. of girls 211 814 475
If a family is chosen at random, compute the probability that it has: (i) No girl (ii) 1 girl (iii) 2 girls (iv) At most one girl (v) More girls than boys Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

We know, Probability of an event = (Number of Favorable outcomes) / (Total Numbers of outcomes) In this case, total numbers of outcomes = 211 + 814 + 475 = 1500. (Here, total numbers of outcomes = total number of families) (i) Probability of having no girl = 211/1500 = 0.1406 (ii) Probability of having 1 girl = 814/1500 = 0.5426 (iii) Probability of having 2 girls = 475/1500 = 0.3166 (iv) Probability of having at the most one girl = (211+814) /1500 = 1025/1500 = 0.6833 (v) Probability of having more girls than boys = 475/1500 = 0.31

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