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RD Sharma Solutions Class 9 Mathematics Solutions for Probability Exercise 25.1 in Chapter 25 - Probability
Question 1 Probability Exercise 25.1
1500 families with 2 children were selected randomly, and the following data were recorded:
| no. of girls in a family | 0 | 1 | 2 |
|---|---|---|---|
| no. of girls | 211 | 814 | 475 |
Answer:
We know, Probability of an event = (Number of Favorable outcomes) / (Total Numbers of outcomes) In this case, total numbers of outcomes = 211 + 814 + 475 = 1500. (Here, total numbers of outcomes = total number of families) (i) Probability of having no girl = 211/1500 = 0.1406 (ii) Probability of having 1 girl = 814/1500 = 0.5426 (iii) Probability of having 2 girls = 475/1500 = 0.3166 (iv) Probability of having at the most one girl = (211+814) /1500 = 1025/1500 = 0.6833 (v) Probability of having more girls than boys = 475/1500 = 0.31
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