Rd sharma solutions
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Circles | Circles Exercise 16.3

Question 1

A circular park of radius 40 m is situated in a colony. Three boys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other. Find the length of the string of each phone.

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[[> widgSince, AB = BC = CA. So, ABC is an equilateral triangle Radius = OA = 40 m (Given)

We know, medians of equilateral triangle pass through the circumcentre and intersect each other at

the ratio 2 : 1.

Here AD is the median of equilateral triangle ABC, we can write:

OA/OD = 2/1

or 40/OD = 2/1

or OD = 20 m

Therefore, AD = OA + OD = (40 + 20) m = 60 m

Now, In ΔADC: By Pythagoras theorem, et id="1" <]]

Therefore, length of string of each phone will be 40√3 m.

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Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 1

A circular park of radius 40 m is situated in a colony. Three boys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other. Find the length of the string of each phone.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

[[> widgSince, AB = BC = CA. So, ABC is an equilateral triangle Radius = OA = 40 m (Given)

We know, medians of equilateral triangle pass through the circumcentre and intersect each other at

the ratio 2 : 1.

Here AD is the median of equilateral triangle ABC, we can write:

OA/OD = 2/1

or 40/OD = 2/1

or OD = 20 m

Therefore, AD = OA + OD = (40 + 20) m = 60 m

Now, In ΔADC: By Pythagoras theorem, et id="1" <]]

Therefore, length of string of each phone will be 40√3 m.

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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