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RD Sharma Solutions Class 9 Mathematics Solutions for Circles Exercise 16.3 in Chapter 16 - Circles

Question 1 Circles Exercise 16.3

A circular park of radius 40 m is situated in a colony. Three boys Ankur, Amit and Anand are sitting at equal distance on its boundary each having a toy telephone in his hands to talk to each other. Find the length of the string of each phone.

Answer:

[[> widgSince, AB = BC = CA. So, ABC is an equilateral triangle Radius = OA = 40 m (Given)

We know, medians of equilateral triangle pass through the circumcentre and intersect each other at

the ratio 2 : 1.

Here AD is the median of equilateral triangle ABC, we can write:

OA/OD = 2/1

or 40/OD = 2/1

or OD = 20 m

Therefore, AD = OA + OD = (40 + 20) m = 60 m

Now, In ΔADC: By Pythagoras theorem, et id="1" <]]

R D Sharma Solutions - Mathematics - Class 9 chapter Circles Question 1 Solution image

Therefore, length of string of each phone will be 40√3 m.

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