The difference between the squares of two consecutive numbers is 31. Find the numbers.
Let the two consecutive numbers be x and (x – 1)
So now,
x2 – (x-1)2 = 31
By using the formula (a-b)2 = a2 + b2 – 2ab
x2 – (x2 – 2x + 1) = 31
x2 – x2 + 2x – 1 = 31
2x – 1 = 31
2x = 31+1
2x = 32
x = 32/2
= 16
Two consecutive numbers are, x and (x-1) : 16 and (16-1) =15
∴ The two consecutive numbers are 16 and 15.
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