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RD Sharma Solutions Class 8 Mathematics Solutions for Data Handling Probability Exercise 26.1 in Chapter 26 - Data Handling Probability

Question 4 Data Handling Probability Exercise 26.1

Three coins are tossed together. Find the probability of getting:

(i) exactly two heads

(ii) at least two heads

(iii) at least one head and one tail

(iv)no tails

Answer:

(i) Exactly two heads

Possible outcome of tossing three coins are: HTT, HHT, HHH, HTH, TTT, TTH, THT, THH

Number of outcomes of exactly two heads are: 3

Probability of getting exactly two heads is = Total numbers/Total number of outcomes

= 3/8

∴ Probability of getting exactly two heads is 3/8

(ii) At least two heads

Possible outcome of tossing three coins are: HTT, HHT, HHH, HTH, TTT, TTH, THT, THH

Number of outcomes of at least two heads are: 4

Probability of getting at least two heads is = Total numbers/Total number of outcomes

= 4/8

= 1/2

∴ Probability of getting at least two heads is 1/2

(iii) At least one head and one tail

Possible outcome of tossing three coins are: HTT, HHT, HHH, HTH, TTT, TTH, THT, THH

Number of outcomes of at least one head and one tail are: 6

Probability of getting at least one head and one tail is = Total numbers/Total number of outcomes

= 6/8

= 3/4

∴ Probability of getting at least one head and one tail is 3/4

(iv) No tails

Possible outcome of tossing three coins are: HTT, HHT, HHH, HTH, TTT, TTH, THT, THH

Number of outcomes of no tails are: 1

Probability of getting no tails is = Total numbers/Total number of outcomes

= 1/8

∴ Probability of getting no tails is 1/8

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