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Rd sharma solutions
Grade 8 
Mathematics
Mathematics class 8th RD Sharma
Surface Area and Volume of Right Circular Cylinder
Surface Area and Volume of Right Circular Cylinder Exercise 22.2
Question 39
Mathematics
Mathematics class 8th RD Sharma
Surface Area and Volume of Right Circular Cylinder
Surface Area and Volume of Right Circular Cylinder Exercise 22.2
Question 39
Surface Area and Volume of Right Circular Cylinder | Surface Area and Volume of Right Circular Cylinder Exercise 22.2
Question 39
CHAPTERS
6. Algebraic Expressions and Identities
8. Division of Algebraic Expressions
9. Linear Equation in One Variable
10. Direct and Inverse Variations
13. Profit Loss Discount and Value Added Tax
15. Understanding Shapes Polygons
16. Understanding Shapes Quadrilaterals
17. Understanding Shapes Special Types Quadrilaterals
20. Area of Trapezium and Polygon
21. Volume Surface Area Cuboid Cube
22. Surface Area and Volume of Right Circular Cylinder
23. Classification And Tabulation Of Data
24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs
2.2 cubic dm of brass is to be drawn into a cylindrical wire 0.25 cm in diameter. Find the length of the wire.
We have,
Diameter of cylindrical wire = 0.25 cm
Radius of wire = d/2 = 0.25/2 = 0.125cm
Let length of wire be ‘h’ cm
Volume of brass wire = 2.2 dm3 = 2200 cm3
πr2h = 2200
22/7 × 0.125 × 0.125 × h = 2200
h = 2200×7 / 22×0.125×0.125
= 15400 / 0.34375
= 44800 cm
= 448m
∴ Length of the wire is 448m.
Algebraic Expressions and Identities
Division of Algebraic Expressions
Linear Equation in One Variable
Profit Loss Discount and Value Added Tax
Understanding Shapes Quadrilaterals
Understanding Shapes Special Types Quadrilaterals
Volume Surface Area Cuboid Cube
Surface Area and Volume of Right Circular Cylinder
Classification And Tabulation Of Data
Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
Pictorial Representation Of Data As Pie Charts Or Circle Graphs
Question 39
2.2 cubic dm of brass is to be drawn into a cylindrical wire 0.25 cm in diameter. Find the length of the wire.
We have,
Diameter of cylindrical wire = 0.25 cm
Radius of wire = d/2 = 0.25/2 = 0.125cm
Let length of wire be ‘h’ cm
Volume of brass wire = 2.2 dm3 = 2200 cm3
πr2h = 2200
22/7 × 0.125 × 0.125 × h = 2200
h = 2200×7 / 22×0.125×0.125
= 15400 / 0.34375
= 44800 cm
= 448m
∴ Length of the wire is 448m.
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