RD Sharma Solutions Class 8 Mathematics Solutions for Surface Area and Volume of Right Circular Cylinder Exercise 22.2 in Chapter 22 - Surface Area and Volume of Right Circular Cylinder

Question 23 Surface Area and Volume of Right Circular Cylinder Exercise 22.2

A cylindrical container with diameter of base 56 cm contains sufficient water to submerge a rectangular solid of iron with dimensions 32 cm×22 cm×14 cm. Find the rise in the level of the water when the solid is completely submerged.

We have,

Diameter of base of cylindrical vessel = 56 cm

Radius of base = d/2 = 56/2 = 28cm

Dimensions of rectangular solid vessel = 32cm × 22cm × 14cm Volume of rectangular solid vessel = 32 × 22 × 14 = 9856 cm3

Let the rise of water level be ‘h’ cm

Volume of cylindrical container = Volume of rectangular solid vessel

πr2h = 9856

22/7 × 28 × 28 × h = 9856

h = 9856×7 / 22×28×28

= 68992 / 17248

= 4cm

∴ Rise in water level is 4cm.

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