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Area of Trapezium and Polygon | Area of Trapezium and Polygon Exercise 20.1

Question 4

A rectangular piece is 20 m long and 15 m wide. From its four corners, quadrants of radii 3.5 m have been cut. Find the area of the remaining part.

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  • Solution

  • Transcript

Area of the plot = Area of the rectangle - 4 × area of one quadrant

Radius of semi-circle = 3.5 m

Area of four quadrants = area of one circle

Area of the plot = Length × Breadth - πr2

Area of the plot = 20 × 15 – (22/7 × 3.5 × 3.5)

Area of the plot = 300 – 38.5 = 261.5 m2

"hello students i am rita your maths lido tutor today's question is a rectangular piece is 20 meter long and 15 meter wide from its four corners quadrants of radii 3.5 meter have been cut find the area of the remaining part first of all we draw a rectangular piece of land so this is a rectangle a b c and d from its four corners this one this one b and c these four quadrants having radii 3.5 meter have been cut out from its four corners we have to find out the area of the shaded path okay so in this question first of all area of shaded part is equal to area of rectangle minus area of 4 quadrant when we use this four quadrant it forms a complete square like this therefore area of rectangle is length into breadth and area of four quadrant is area of circle that is pi r square area of rectangle length is 20 meter and the breadth is 15 meter minus 5 the value of pi is 22 by 7 and the radius is 3.5 meter 3.5 into five so cancel out seven when the seven and seven fives are 35 0.5 20 into 15 it becomes 300 minus when we multiply 22 into 0.5 and into 3.5 it becomes 38.5 now we subtract 300 minus 38.5 then we get 261.5 meter squared so this is the answer area of shaded path i hope you enjoyed this video i will see you in next session until then stay safe bye "

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Question 4

A rectangular piece is 20 m long and 15 m wide. From its four corners, quadrants of radii 3.5 m have been cut. Find the area of the remaining part.

  • Solution

  • Transcript

Area of the plot = Area of the rectangle - 4 × area of one quadrant

Radius of semi-circle = 3.5 m

Area of four quadrants = area of one circle

Area of the plot = Length × Breadth - πr2

Area of the plot = 20 × 15 – (22/7 × 3.5 × 3.5)

Area of the plot = 300 – 38.5 = 261.5 m2

"hello students i am rita your maths lido tutor today's question is a rectangular piece is 20 meter long and 15 meter wide from its four corners quadrants of radii 3.5 meter have been cut find the area of the remaining part first of all we draw a rectangular piece of land so this is a rectangle a b c and d from its four corners this one this one b and c these four quadrants having radii 3.5 meter have been cut out from its four corners we have to find out the area of the shaded path okay so in this question first of all area of shaded part is equal to area of rectangle minus area of 4 quadrant when we use this four quadrant it forms a complete square like this therefore area of rectangle is length into breadth and area of four quadrant is area of circle that is pi r square area of rectangle length is 20 meter and the breadth is 15 meter minus 5 the value of pi is 22 by 7 and the radius is 3.5 meter 3.5 into five so cancel out seven when the seven and seven fives are 35 0.5 20 into 15 it becomes 300 minus when we multiply 22 into 0.5 and into 3.5 it becomes 38.5 now we subtract 300 minus 38.5 then we get 261.5 meter squared so this is the answer area of shaded path i hope you enjoyed this video i will see you in next session until then stay safe bye "

Our top 5% students will be awarded a special scholarship to Lido.

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