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Area of Trapezium and Polygon | Area of Trapezium and Polygon Exercise 20.1

Question 13

A rectangular grassy plot is 112 m long and 78 m broad. It has gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs. 4.50 per square metre.

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  • Solution

  • Transcript

We know that,

Inner area of rectangle = length × breadth Inner area of rectangle = 112 × 78 = 8736 m2

Width of path = 2.5 m

Length of outer rectangle = 112 – (2.5 + 2.5) = 107 m

Breadth of outer rectangle = 78 – (2.5 + 2.5) = 73 m And,

Outer area of rectangle = length × breadth

Outer area of rectangle = 107 × 73 = 7811 m2

Now let’s calculate

Area of path,

Area of path = Outer area of rectangle – Inner area of rectangle

Area of path = 8736 – 7811 = 925 m2

Also given that,

Cost of construction for 1 m2 = Rs 4.50

∴ Cost of construction for 925 m2 = 925 × 4.50 = Rs 4162.5

"hello students i am rita your mass leader tutor and the today's question is a rectangular glassy plot is 112 meter long and 78 meter broad it has gravel path 2.5 meter wide all around it on this side find the area of the path and the cost of constructing it at rupees 4.50 per square meter so in this question this is a rectangle and this is the path all around it so the length is given to us 112 meter and the breadth is given to us 78 meter and this is a path of 2.5 meter this is also 2.5 2.5 and 2.5 okay we have to find the area of the path and the cost of the constructing it at rupees 4.50 per square meter so the area of path area of path is equal to area of outer rectangle outer minus inner rectangle there are two rectangles outer and inner when we subtract inner from outer then we got the area of the path so area of outer rectangle is length into breadth capital length that is 112 meter into 78 meter and the length of inner rectangle this inner rectangle is when we subtract 112 minus 2.5 plus 2.5 so this is the length of inner rectangle you need this one so 112 minus 5 it becomes 107 107 meter into similarly we find the breadth also breadth is 78 minus 5 then we got 73 meter 73 meter now we solve this equation 112 into 78 we got 8736 and 107 into 73 we got 7811. when we subtract 8736 minus 7 811 we got 925 meter square and we know that cost of construction cost of construction per square meter is 4.50 so the cost of construction of 9 to 5 meter square is equal to rupees nine to five multiply four point five zero so then we multiply nine to five into four point five zero we got four thousand one hundred sixty two point five zero so this is our answer i hope you liked the video so please subscribe video for more updates and do comment your questions thank you"

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Question 13

A rectangular grassy plot is 112 m long and 78 m broad. It has gravel path 2.5 m wide all around it on the side. Find the area of the path and the cost of constructing it at Rs. 4.50 per square metre.

  • Solution

  • Transcript

We know that,

Inner area of rectangle = length × breadth Inner area of rectangle = 112 × 78 = 8736 m2

Width of path = 2.5 m

Length of outer rectangle = 112 – (2.5 + 2.5) = 107 m

Breadth of outer rectangle = 78 – (2.5 + 2.5) = 73 m And,

Outer area of rectangle = length × breadth

Outer area of rectangle = 107 × 73 = 7811 m2

Now let’s calculate

Area of path,

Area of path = Outer area of rectangle – Inner area of rectangle

Area of path = 8736 – 7811 = 925 m2

Also given that,

Cost of construction for 1 m2 = Rs 4.50

∴ Cost of construction for 925 m2 = 925 × 4.50 = Rs 4162.5

"hello students i am rita your mass leader tutor and the today's question is a rectangular glassy plot is 112 meter long and 78 meter broad it has gravel path 2.5 meter wide all around it on this side find the area of the path and the cost of constructing it at rupees 4.50 per square meter so in this question this is a rectangle and this is the path all around it so the length is given to us 112 meter and the breadth is given to us 78 meter and this is a path of 2.5 meter this is also 2.5 2.5 and 2.5 okay we have to find the area of the path and the cost of the constructing it at rupees 4.50 per square meter so the area of path area of path is equal to area of outer rectangle outer minus inner rectangle there are two rectangles outer and inner when we subtract inner from outer then we got the area of the path so area of outer rectangle is length into breadth capital length that is 112 meter into 78 meter and the length of inner rectangle this inner rectangle is when we subtract 112 minus 2.5 plus 2.5 so this is the length of inner rectangle you need this one so 112 minus 5 it becomes 107 107 meter into similarly we find the breadth also breadth is 78 minus 5 then we got 73 meter 73 meter now we solve this equation 112 into 78 we got 8736 and 107 into 73 we got 7811. when we subtract 8736 minus 7 811 we got 925 meter square and we know that cost of construction cost of construction per square meter is 4.50 so the cost of construction of 9 to 5 meter square is equal to rupees nine to five multiply four point five zero so then we multiply nine to five into four point five zero we got four thousand one hundred sixty two point five zero so this is our answer i hope you liked the video so please subscribe video for more updates and do comment your questions thank you"

Our top 5% students will be awarded a special scholarship to Lido.

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