Mariam bought two fans for Rs 3605. She sold one at a profit of 15% and theother at a loss of 9%. If Mariam obtained the same amount for each fan, find thecost price of each fan.
Given, cost price of 2 fans is = Rs 3605
Let cost price of 1 fan be = Rs x
Then CP of other fan will be = Rs 3605 – x
We know that one is a gain and other is a loss.
Selling price of first fan (gain) = x + x×15/100
= x + x×3/20
= (20x+3x)/20
= Rs 23x/20
Selling price of second fan (loss) = (3605 - x) × 91/100
= Rs (3605×91 – 91x)/100
So now, by equating both we get,
23x/20 = (3605×91 – 91x)/100
23x = (3605×91 – 91x)/5
23x × 5 = 3605×91 – 91x
115x + 91x = 3605×91
206x = 3605×91
x = (3605×91)/206
= 1592.50
∴ Cost price of one fan (x) is = Rs 1592.50
Cost price of second fan (3605 - x) is = 3605 – 1592.50 = Rs 2012.50
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