Jump to

- Rational Numbers
- Powers
- Squares and Square Roots
- Cube and Cube Roots
- Playing with Numbers
- Algebraic Expressions and Identities
- Factorization
- Division of Algebraic Expressions
- Linear Equation in One Variable
- Direct and Inverse Variations
- Time and Work
- Percentage
- Profit Loss Discount and Value Added Tax
- Compound Interest
- Understanding Shapes Polygons
- Understanding Shapes Quadrilaterals
- Understanding Shapes Special Types Quadrilaterals
- Practical Goemetry
- Visualising Shapes
- Area of Trapezium and Polygon
- Volume Surface Area Cuboid Cube
- Surface Area and Volume of Right Circular Cylinder
- Classification And Tabulation Of Data
- Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
- Pictorial Representation Of Data As Pie Charts Or Circle Graphs
- Data Handling Probability
- Introduction To Graphs

Mariam bought two fans for Rs 3605. She sold one at a profit of 15% and theother at a loss of 9%. If Mariam obtained the same amount for each fan, find thecost price of each fan.

Answer:

Given, cost price of 2 fans is = Rs 3605

Let cost price of 1 fan be = Rs x

Then CP of other fan will be = Rs 3605 – x

We know that one is a gain and other is a loss.

Selling price of first fan (gain) = x + x×15/100

= x + x×3/20

= (20x+3x)/20

= Rs 23x/20

Selling price of second fan (loss) = (3605 - x) × 91/100

= Rs (3605×91 – 91x)/100

So now, by equating both we get,

23x/20 = (3605×91 – 91x)/100

23x = (3605×91 – 91x)/5

23x × 5 = 3605×91 – 91x

115x + 91x = 3605×91

206x = 3605×91

x = (3605×91)/206

= 1592.50

∴ Cost price of one fan (x) is = Rs 1592.50

Cost price of second fan (3605 - x) is = 3605 – 1592.50 = Rs 2012.50

"hello students i am rita your master
tutor and the today's question is
maryam bought two fans for rupees 3605
she showed one or one at a profit of 15
percent and the other at the loss of
nine percent
if mariam obtained the same amount for
each fan
find the cost price of each fan first of
all
let cost price of first
fan that is cpu one is equal to rupees
x then the cost price
of second fan will become
rupees 3605
minus x okay
and in the first one he she got a profit
of 15 percent
and the second one she got a loss of
nine percent okay so first of all we
find the sp1 setting price of first fan
is
100 plus probably put the formula of sp
100 plus profit percent divided by
100 into cp cp is x so it becomes so sp1
is equal to 100 plus 15 that is 115 by
100
x this is our sp1 now we find the sp2
100 minus loss percent divided by 100
into cp2 cp2 is 3605
minus x so sp2
is equal to 100 minus 991
by 100 3605
minus x but in the question it is given
that
the selling price is same of for each
fan then according to question it is
given that
sp1 is equal to sp2
now we solve this equation sp1
is equal to sp true
now we solve the equation as p1 is
115 by 100x
is equal to sp2 is 91 by 100
bracket 3605
minus x now we solve this 100
cancel out each other so 115 x
is equal to 91 into 3
605 minus 91
x so 115 x plus
91 x is equal to 91
into 3 600
5 and when we add these two then it
becomes 206x
is equal to 91 into 3
605 then it becomes 3 2 8
0 double 5 now the value of x when we
divide
this 3 2 8 0 double divided by
206 then the value of x is equal to
rupees
1592.50
peso so this is the cp
of first fan
is equal to rupees one five nine two
point five
zero then the cp of second one
is equal to rupees three thousand
six hundred five minus
one thousand five hundred ninety two
point fifty
then we got rupees two thousand twelve
point
fifty so this is our answer
i hope you like this video so please
subscribe leader for
more updates and do comment your
questions thank you"

Related Questions

Was This helpful?

Exercises

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved