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RD Sharma Solutions Class 8 Mathematics Solutions for Profit Loss Discount and Value Added Tax Exercise 13.1 in Chapter 13 - Profit Loss Discount and Value Added Tax
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A dealer bought two tables for Rs 3120. He sold one of them at loss of 15% andother at a gain of 36%. Then, he found that each table was sold for the same price.Find the cost price of each table.
Given, the cost price of two tables is = Rs 3120
Let cost price of first table be = Rs x
Then, cost price of second table will be = Rs 3120 – x
We know that one is a gain and other is a loss.
Selling price of first table (gain) = x + x × 36/100
= x +9x/25
= (25x + 9x)/25
= Rs 34x/25
Selling price of second table (loss) = (3120 - x) × 85/100
= Rs (3120×85 – 85x)/100
So now, by equating both we get,
34x/25 = (3120×85 – 85x)/100
34x = (3120×85 – 85x)/4
34x × 4 = 3120×85 – 85x
136x + 85x = 3120×85
221x = 3120×85
x = (3120×85)/221
= 1200
∴ Cost price of first table (x) is = Rs 1200
Cost price of second table (3120 - x) = 3120 – 1200 = Rs 1920
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