 # RD Sharma Solutions Class 8 Mathematics Solutions for Profit Loss Discount and Value Added Tax Exercise 13.1 in Chapter 13 - Profit Loss Discount and Value Added Tax

Question 17 Profit Loss Discount and Value Added Tax Exercise 13.1

A dealer bought two tables for Rs 3120. He sold one of them at loss of 15% andother at a gain of 36%. Then, he found that each table was sold for the same price.Find the cost price of each table.

Given, the cost price of two tables is = Rs 3120

Let cost price of first table be = Rs x

Then, cost price of second table will be = Rs 3120 – x

We know that one is a gain and other is a loss.

Selling price of first table (gain) = x + x × 36/100

= x +9x/25

= (25x + 9x)/25

= Rs 34x/25

Selling price of second table (loss) = (3120 - x) × 85/100

= Rs (3120×85 – 85x)/100

So now, by equating both we get,

34x/25 = (3120×85 – 85x)/100

34x = (3120×85 – 85x)/4

34x × 4 = 3120×85 – 85x

136x + 85x = 3120×85

221x = 3120×85

x = (3120×85)/221

= 1200

∴ Cost price of first table (x) is = Rs 1200

Cost price of second table (3120 - x) = 3120 – 1200 = Rs 1920

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