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A motorist travelled 122 kilometers before his first stop. If he had 10%of hisjourney to complete at this point, how long was the total ride?

Answer:

Given details are,

Motorist total distance travelled before first stop = 122 km

Journey completed at first stop = 10 %

Let us consider total ride to be travelled be ‘x’ km

So, by calculating

(x/100) × 10 = 122

By cross multiplying we get,

x/100 = 122/10

x = (122 × 100)/10

= 1220 km

∴ Motorist total ride is 1220 km

"hello students i am rita your mass
leader tutor
and the today's question is a motorist
travel 122 kilometers
before his first stop if he had
10 percent of his journey to complete
at this point how long was the total
right
so first of all we let the
total right
let the total right distance
is equal to x kilometer
so according to question it is given
that
10 percent of
x is equal to 122
kilo meter 122 kilometer is the
10 of the total rate so
we solve this equation is equal to 122
0 0 cancel out so x is equal to 1220
kilo newton so this is our answer the x
that is total right is
total distance is one thousand two
twenty i hope you like this video so
please subscribe video for more updates
and do comment your questions thank you"

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