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Rd sharma solutions
Grade 8 
Mathematics
Mathematics class 8th RD Sharma
Time and Work
Time and Work Exercise 11.1
Question 15
Mathematics
Mathematics class 8th RD Sharma
Time and Work
Time and Work Exercise 11.1
Question 15
Time and Work | Time and Work Exercise 11.1
Question 15
CHAPTERS
6. Algebraic Expressions and Identities
8. Division of Algebraic Expressions
9. Linear Equation in One Variable
10. Direct and Inverse Variations
13. Profit Loss Discount and Value Added Tax
15. Understanding Shapes Polygons
16. Understanding Shapes Quadrilaterals
17. Understanding Shapes Special Types Quadrilaterals
20. Area of Trapezium and Polygon
21. Volume Surface Area Cuboid Cube
22. Surface Area and Volume of Right Circular Cylinder
23. Classification And Tabulation Of Data
24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs
A and B can do a piece of work in 6 days and 4 days respectively. A started thework, worked at it for 2 days and then was joined by B. Find the total time taken tocomplete the work.
The given details are,
A can do a piece of work in = 6 days
A’s 1 day work = 1/6
B can do a piece of work in = 4 days
In 2 days the work completed by A = 2 × 1/6 = 1/3
part of work Remaining work = 1 – 1/3
= (3-1)/3
= 2/3
A and B can finish the remaining work in = (2/3)/(1/6 + 1/4)
= (2/3)/(5/12)
= (2×12)/(3×5)
= 8/5 days
∴ Total time taken to complete the work by A and B = 2 + 8/5
= (10+8)/5 = 18/5
= 3 3/5 days
Algebraic Expressions and Identities
Division of Algebraic Expressions
Linear Equation in One Variable
Profit Loss Discount and Value Added Tax
Understanding Shapes Quadrilaterals
Understanding Shapes Special Types Quadrilaterals
Volume Surface Area Cuboid Cube
Surface Area and Volume of Right Circular Cylinder
Classification And Tabulation Of Data
Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
Pictorial Representation Of Data As Pie Charts Or Circle Graphs
Question 15
A and B can do a piece of work in 6 days and 4 days respectively. A started thework, worked at it for 2 days and then was joined by B. Find the total time taken tocomplete the work.
The given details are,
A can do a piece of work in = 6 days
A’s 1 day work = 1/6
B can do a piece of work in = 4 days
In 2 days the work completed by A = 2 × 1/6 = 1/3
part of work Remaining work = 1 – 1/3
= (3-1)/3
= 2/3
A and B can finish the remaining work in = (2/3)/(1/6 + 1/4)
= (2/3)/(5/12)
= (2×12)/(3×5)
= 8/5 days
∴ Total time taken to complete the work by A and B = 2 + 8/5
= (10+8)/5 = 18/5
= 3 3/5 days
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