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A can do a piece of work in 40 days and B in 45 days. They work together for 10days and then B goes away. In how many days will A finish the remaining work?

Answer:

The given details are,

Aasheesh can paint his doll in = 20 minutes

Aasheesh can paint his doll in 1 minute = 1/20

Chinki can paint the same doll in = 25 minutes

Chinki can paint the same doll in 1 minute = 1/25

Together they both can paint the doll in 1 minute = 1/20 + 1/25

= (5+4)/100 (by taking LCM for 20 and

25 which is 100)

= 9/100

Work done by them in 5 minute = 5 × 9/100

= 9/20

Remaining work = 1 – 9/20

= (20-9)/20

= 11/20

∴ Aasheesh can paint the remaining doll in = (11/20)/(1/20)

= 11/20 × 20

= 11minutes

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