Video transcript
"hello dear students i am sunita nair
from Lido learning
i am here to help you solve a problem in
in
variation which goes like this
55 cows can graze a field in 16 days
how many cows will graze the same field
in 10 days
now let's put in the information that we
have in this table
next to the picture of the cows grazing
in the field so here we have
55 cows can graze a field
in 16 days
so the question is how many cows
will graze the same field in 10 days
so let that number of cows which will
graze
the same field in 10 days be x
so we have to find the value of x now we
know
that if the grass in the field
is sufficient for 55 cows
for a time of 16 days
then if the same field
should be sufficient only for 10 days
we would need a greater number of cows
to graze the field isn't it for the food
or for the grass to last only 10 days
we would need a greater number of cows
so in this case we can see that as a
number of cows
increase the
the time for which they can graze in the
same field
will reduce so when you have
quantities like this
which vary inversely
if p and q vary inversely that is if
as p increases q decreases
or if as q increases
p decreases then we say that these two
quantities are in
inverse variation
and in such a case the
proportionality constant is given by
p into q
so going back to our problem
we know that our p is 16 and our q
is 55 so 16 into 55
should be a constant the same constant
should be given by
the product of 10 into
x
so x if we solve for x we will get x
equal to 16 into 55
divided by 10.
so reducing this expression
we get the answer is 88
cows 88 cows
will graze the same field in 10 days
so our answer is 88 i hope you
understood the solution to this problem
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"