Jump to

- Rational Numbers
- Powers
- Squares and Square Roots
- Cube and Cube Roots
- Playing with Numbers
- Algebraic Expressions and Identities
- Factorization
- Division of Algebraic Expressions
- Linear Equation in One Variable
- Direct and Inverse Variations
- Time and Work
- Percentage
- Profit Loss Discount and Value Added Tax
- Compound Interest
- Understanding Shapes Polygons
- Understanding Shapes Quadrilaterals
- Understanding Shapes Special Types Quadrilaterals
- Practical Goemetry
- Visualising Shapes
- Area of Trapezium and Polygon
- Volume Surface Area Cuboid Cube
- Surface Area and Volume of Right Circular Cylinder
- Classification And Tabulation Of Data
- Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
- Pictorial Representation Of Data As Pie Charts Or Circle Graphs
- Data Handling Probability
- Introduction To Graphs

55 cows can graze a field in 16 days. How many cows will graze the same field in 10 days?

Answer:

Let number of cows be ‘x’ cows

We know k = xy

16 × 55 = 10 × x

x = (16×55)/10

= 88

∴ 88 cows can graze the same field in 10 days.

"hello dear students i am sunita nair
from Lido learning
i am here to help you solve a problem in
in
variation which goes like this
55 cows can graze a field in 16 days
how many cows will graze the same field
in 10 days
now let's put in the information that we
have in this table
next to the picture of the cows grazing
in the field so here we have
55 cows can graze a field
in 16 days
so the question is how many cows
will graze the same field in 10 days
so let that number of cows which will
graze
the same field in 10 days be x
so we have to find the value of x now we
know
that if the grass in the field
is sufficient for 55 cows
for a time of 16 days
then if the same field
should be sufficient only for 10 days
we would need a greater number of cows
to graze the field isn't it for the food
or for the grass to last only 10 days
we would need a greater number of cows
so in this case we can see that as a
number of cows
increase the
the time for which they can graze in the
same field
will reduce so when you have
quantities like this
which vary inversely
if p and q vary inversely that is if
as p increases q decreases
or if as q increases
p decreases then we say that these two
quantities are in
inverse variation
and in such a case the
proportionality constant is given by
p into q
so going back to our problem
we know that our p is 16 and our q
is 55 so 16 into 55
should be a constant the same constant
should be given by
the product of 10 into
x
so x if we solve for x we will get x
equal to 16 into 55
divided by 10.
so reducing this expression
we get the answer is 88
cows 88 cows
will graze the same field in 10 days
so our answer is 88 i hope you
understood the solution to this problem
please visit our channel regularly you
will find many more
homework solutions being explained to
you you can subscribe
to our channel for updates as well
thank you
"

Related Questions

Chapters

Lido

Courses

Quick Links

Terms & Policies

Terms & Policies

2022 © Quality Tutorials Pvt Ltd All rights reserved