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CHAPTERS
6. Algebraic Expressions and Identities
8. Division of Algebraic Expressions
9. Linear Equation in One Variable
10. Direct and Inverse Variations
13. Profit Loss Discount and Value Added Tax
15. Understanding Shapes Polygons
16. Understanding Shapes Quadrilaterals
17. Understanding Shapes Special Types Quadrilaterals
20. Area of Trapezium and Polygon
21. Volume Surface Area Cuboid Cube
22. Surface Area and Volume of Right Circular Cylinder
23. Classification And Tabulation Of Data
24. Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
25. Pictorial Representation Of Data As Pie Charts Or Circle Graphs
A car can finish a certain journey in 10 hours at the speed of 48 km/hr. By how much should its speed be increased so that it may take only 8 hours to cover the same distance?
Solution
Transcript
Let us consider the speed of the car as ‘x’ km/hr.
We know k = xy
10 × 48 = 8 × x
x = (10×48)/8
= 60
Increased speed = 60 – 48 = 12km/hr.
∴ The speed should be increased by 12 km/hr. to cover the same distance.
"Hello, dear student and Sunita 9 from Lido learning. I'm here to help you solve a sum in inverse variation. It goes like this a car can finish a certain journey in 10 hours at the speed of 48 km/h by how much should it speed be increased so that it may take only eight hours to cover the same distance. So as you can see, I have made a table over here. Let's fill in the values that we have been given. So here we have that a car can finish a certain journey in 10 hours. When the speed is 48 kilometers per hour. Right The question is by how much should it speed be increased so that it may take only 8 hours to cover the same distance. So we shall put eight in the second column. And the new speed by which it can reach its destination in 8 hours Let's denote that by X. Alright now this First Column I have left . To explain the concept of constant the constant in constant of variation in the case of inverse variation now when we look at the speed and time We know that as the speed increases. The time to reach a certain destination will decrease right? So here we have. If the speed is 48 and the destination is reached in 10 hours. To reach the destination in a lesser time that is 8 hours. We will need to increase the speed. So this is a case of inverse variation. So inverse variation is as one. As one quantity P increases and the other quantity Q decreases related quantity Q decreases then P into Q is the constant of proportionality. So in this case, what is our constant of proportionality constant of proportionality is 10 into 48. So since it's a constant 8 into X also should be equal to the same constant. So these two should be equal. Okay, so we have we have this equation here now X is our unknown. So what is x equal to X will be equal to 10 into 48. / it So eat ones I ate it six is a 48. I have 10 into 6, which is 60 kilometers per hour since X is the speed I will. Give it the unit kilometers per hour. Now the question is by how much should it speed be increased? So what was the former speed? The former speed was 48 kilometers per hour. And the new speed is 60 kilometers per hour or the increased speed So By how much you did speed B increase the question is. By how much should the speed be increased? You see this by how much should the speed be increased? So that will be The difference of the new speed and the old So the speed Should be increased. Bye. 60 - 48 Kilometers per hour Which is Twelve So the speech should be increased by 12 kilometers per hour so that the car will reach the same destination in eight hours instead of 10 hours. I hope you understood the solution to this problem. Please visit our Channel regularly, you will find many more such homework solutions being explained to you. Do subscribe to our YouTube channel for updates as well. Thank you."
Algebraic Expressions and Identities
Division of Algebraic Expressions
Linear Equation in One Variable
Profit Loss Discount and Value Added Tax
Understanding Shapes Quadrilaterals
Understanding Shapes Special Types Quadrilaterals
Volume Surface Area Cuboid Cube
Surface Area and Volume of Right Circular Cylinder
Classification And Tabulation Of Data
Classification And Tabulation Of Data Graphical Representation Of Data As Histograms
Pictorial Representation Of Data As Pie Charts Or Circle Graphs
A car can finish a certain journey in 10 hours at the speed of 48 km/hr. By how much should its speed be increased so that it may take only 8 hours to cover the same distance?
Solution
Transcript
Let us consider the speed of the car as ‘x’ km/hr.
We know k = xy
10 × 48 = 8 × x
x = (10×48)/8
= 60
Increased speed = 60 – 48 = 12km/hr.
∴ The speed should be increased by 12 km/hr. to cover the same distance.
"Hello, dear student and Sunita 9 from Lido learning. I'm here to help you solve a sum in inverse variation. It goes like this a car can finish a certain journey in 10 hours at the speed of 48 km/h by how much should it speed be increased so that it may take only eight hours to cover the same distance. So as you can see, I have made a table over here. Let's fill in the values that we have been given. So here we have that a car can finish a certain journey in 10 hours. When the speed is 48 kilometers per hour. Right The question is by how much should it speed be increased so that it may take only 8 hours to cover the same distance. So we shall put eight in the second column. And the new speed by which it can reach its destination in 8 hours Let's denote that by X. Alright now this First Column I have left . To explain the concept of constant the constant in constant of variation in the case of inverse variation now when we look at the speed and time We know that as the speed increases. The time to reach a certain destination will decrease right? So here we have. If the speed is 48 and the destination is reached in 10 hours. To reach the destination in a lesser time that is 8 hours. We will need to increase the speed. So this is a case of inverse variation. So inverse variation is as one. As one quantity P increases and the other quantity Q decreases related quantity Q decreases then P into Q is the constant of proportionality. So in this case, what is our constant of proportionality constant of proportionality is 10 into 48. So since it's a constant 8 into X also should be equal to the same constant. So these two should be equal. Okay, so we have we have this equation here now X is our unknown. So what is x equal to X will be equal to 10 into 48. / it So eat ones I ate it six is a 48. I have 10 into 6, which is 60 kilometers per hour since X is the speed I will. Give it the unit kilometers per hour. Now the question is by how much should it speed be increased? So what was the former speed? The former speed was 48 kilometers per hour. And the new speed is 60 kilometers per hour or the increased speed So By how much you did speed B increase the question is. By how much should the speed be increased? You see this by how much should the speed be increased? So that will be The difference of the new speed and the old So the speed Should be increased. Bye. 60 - 48 Kilometers per hour Which is Twelve So the speech should be increased by 12 kilometers per hour so that the car will reach the same destination in eight hours instead of 10 hours. I hope you understood the solution to this problem. Please visit our Channel regularly, you will find many more such homework solutions being explained to you. Do subscribe to our YouTube channel for updates as well. Thank you."
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