A man 4 times as old as his son. After 16 years, he will be only twice as old as his son. Find their present ages.
Let the present age of the son = x years.
Therefore, the present age of his father = 4xyears.
So, after 16 years,
Son’s age = (x + 16) and father’s age = (4x + 16) years
According to question:
⇒ 4x + 16 = 2(x + 16)
⇒ 4x + 16 = 2x + 32
Transposing 2x to LHS and 16 to RHS, we get
⇒ 4x – 2x = 32 – 16
⇒ 2x = 16
Dividing both sides by 2, we get
⇒ 2x/2 = 16/2
⇒ x = 8
So, the present age of the son = x = 8 years,
And the present age of the father = 4x = 4(8) = 32 years.
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