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RD Sharma Solutions Class 7 Mathematics Solutions for Data Handling-Probability Exercise 25.1 in Chapter 25 - Data Handling-Probability
Question 1 Data Handling-Probability Exercise 25.1
A coin is tossed 1000 times with the following frequencies:
Head: 445, Tail: 555
When a coin is tossed at random, what is the probability of getting?
(i) A head?
(ii) A tail?
Answer:
Given total number of times a coin is tossed = 1000
Number of times a head comes up = 445
Number of times a tail comes up = 555
(i) Probability of getting head = number of heads/total number of trails
= (445/1000)
= 0.445
(ii) Probability of getting tail = number of tail/total number of trails
= (555/1000)
= 0.555
Video transcript
"hey kids welcome to lido q a video
and we need your little tutor bringing
you this question on your screen
in the figure ad is the median
ad is the median therefore bd should be
equal to cd
bm and cr are perpendicular strong
right so these angles are 90 degrees
from b and c respectively and
a d and a d produced okay
not a d and a d but
yeah a d n a d produced prove that b m
equals to c
n so what is given to us
given to us is a d
is the median
okay and angle
bmd is equal to angle
cnd is equal to 90 degrees
to prove we have to prove
bm is equal to cn
so let us look at the proof
in triangle bmd
and triangle c and d
we have bd
equal to dc since
a d is medium
right angle bmd
is equal to angle c and d which is
given to us and
angle bdm is equal to angle
cdn right because they are
vertically opposite
angles now if you look
the side bd
and dc are not included therefore
by angle angle side
congruency
triangle bdm
is congruent to triangle cd
n therefore we can say
bm equal to cn isn't that easy guys
right so if you have a doubt
please leave a comment below i'll see
you in our next video
until then bye kids keep practicing do
like the video and subscribe to our
channel"
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