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Mensuration 2 Area of Circle | Mensuration 2 Exercise 21.1

Question 7

A piece of wire is bent in the shape of an equilateral triangle of each side 6.6 cm. It is re-bent to form a circular ring. What is the diameter of the ring?

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Given side of equilateral triangle = 6.6 cm

Length of the wire = the perimeter of equilateral triangle

Perimeter of equilateral triangle = 3 × side

= 3 × 6.6 = 19.8 cm

Therefore circumference = 19.8 cm

C = 2 π r

19.8 = 2 × (22/7) × r

19.8 = 44/7 r

r = (19.8 × 7)/44

r = 138.6/44

= 3.15 cm

Diameter = 2r

Therefore diameter of ring = 2 × 3.15 = 6.3 cm

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Question 7

A piece of wire is bent in the shape of an equilateral triangle of each side 6.6 cm. It is re-bent to form a circular ring. What is the diameter of the ring?

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given side of equilateral triangle = 6.6 cm

Length of the wire = the perimeter of equilateral triangle

Perimeter of equilateral triangle = 3 × side

= 3 × 6.6 = 19.8 cm

Therefore circumference = 19.8 cm

C = 2 π r

19.8 = 2 × (22/7) × r

19.8 = 44/7 r

r = (19.8 × 7)/44

r = 138.6/44

= 3.15 cm

Diameter = 2r

Therefore diameter of ring = 2 × 3.15 = 6.3 cm

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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