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RD Sharma Solutions Class 7 Mathematics Solutions for Mensuration 1 Exercise 20.1 in Chapter 20 - Mensuration 1
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A door of dimensions 3 m x 2m is on the wall of dimension 10 m x 10 m. Find the cost of painting the wall if rate of painting is Rs 2.50 per sq. m.
Answer:
Given length of the door = 3 m
Also given that breadth of the door = 2 m
Side of the wall = 10 m
We know that Area of the square = (Side)^2
Area of the wall = Side x Side = 10 m x 10 m
= 100 m^2
We know that the area of the rectangle = length x breadth
Area of the door = Length x Breadth = 3 m x 2 m = 6 m^2
Thus, required area of the wall for painting = Area of the wall – Area of the door
= (100 – 6) m^2
= 94 m^2
Rate of painting per square metre = Rs. 2.50
Hence, the cost of painting the wall = Rs. (94 x 2.50) = Rs. 235
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