Rd sharma solutions
Our top 5% students will be awarded a special scholarship to Lido.

Mensuration 1 | Mensuration 1 Exercise 20.1

Question 16

A lane 180 m long and 5 m wide is to be paved with bricks of length 20 cm and breadth 15 cm. Find the cost of bricks that are required, at the rate of Rs 750 per thousand.

Looking to do well in your science exam ?  
Learn from an expert tutor. Book a free class!

Given that length of lane = 180 m

Breadth of the lane = 5 m

Area of a lane = Length x Breadth

= 180 m x 5 m

= 900 m^2

Length of the brick = 20 cm

Breadth of the brick = 15 cm

Area of a brick = Length x Breadth

= 20 cm x 15 cm

= 300 cm^2

= 0.03 m2 [Since 1 m^2 = 10000 cm^2]

Required number of bricks = 900/0.03 = 30000

Cost of 1000 bricks = Rs. 750

Total cost of 30,000 bricks = 750×30,000/1000

= Rs. 22,500

Set your child up for success with Lido, book a class today!

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 16

A lane 180 m long and 5 m wide is to be paved with bricks of length 20 cm and breadth 15 cm. Find the cost of bricks that are required, at the rate of Rs 750 per thousand.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given that length of lane = 180 m

Breadth of the lane = 5 m

Area of a lane = Length x Breadth

= 180 m x 5 m

= 900 m^2

Length of the brick = 20 cm

Breadth of the brick = 15 cm

Area of a brick = Length x Breadth

= 20 cm x 15 cm

= 300 cm^2

= 0.03 m2 [Since 1 m^2 = 10000 cm^2]

Required number of bricks = 900/0.03 = 30000

Cost of 1000 bricks = Rs. 750

Total cost of 30,000 bricks = 750×30,000/1000

= Rs. 22,500

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
Connect with us on social media!
2021 © Quality Tutorials Pvt Ltd All rights reserved
`