A man goes 15 m due west and then 8 m due north. How far is he from the starting point?
Given a man goes 15 m due west and then 8 m due north
Let O be the starting point and P be the final point.
Then OP becomes the hypotenuse in the triangle.
So by using the Pythagoras theorem, we can find the distance OP.
OP^2 = 15^2 + 8^2
OP^2 = 225 + 64
OP^2 = 289
OP = 17
Hence, the required distance is 17 m.
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