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Simple Interest | Simple Interest Exercise 13.1

Question 6

A man borrowed Rs 8000 from a bank at 8% per annum. Find the amount he hasto pay after 4 ½ years.

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Given Principal amount P = Rs 8000

Time period T = 4 ½ years = 9/2 years

Rate of interest R = 8% p.a.

We know that simple interest = (P × T × R)/100

On substituting these values in above equation we get

SI = (8000 × (9/2) × 8)/100

= Rs 2880

Amount = Principal amount + Interest

= Rs 8000 + 2880

= Rs 10880

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Our top 5% students will be awarded a special scholarship to Lido.

subject-cta

Question 6

A man borrowed Rs 8000 from a bank at 8% per annum. Find the amount he hasto pay after 4 ½ years.

Looking to do well in your science exam ? Learn from an expert tutor. Book a free class!

Given Principal amount P = Rs 8000

Time period T = 4 ½ years = 9/2 years

Rate of interest R = 8% p.a.

We know that simple interest = (P × T × R)/100

On substituting these values in above equation we get

SI = (8000 × (9/2) × 8)/100

= Rs 2880

Amount = Principal amount + Interest

= Rs 8000 + 2880

= Rs 10880

Our top 5% students will be awarded a special scholarship to Lido.

subject-cta
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