RD Sharma Solutions Class 7 Mathematics Solutions for Profit and Loss Exercise 12.1 in Chapter 12 - Profit and Loss

Question 15 Profit and Loss Exercise 12.1

A bookseller sells all his books at a profit of 10%. If he buys a book fromthe distributor at Rs 200, how much does he sell it for?

Given profit % = 10% CP = Rs. 200

Since SP = {(100 + profit %) /100} x CP

= {(100 + 10)/100} x 200

= {110/100} x 200 = Rs. 220

The bookseller sells the book for Rs. 220

Video transcript
"hello students welcome to Lido homework so today's question is a bookseller sells all his books at a profit of 10 percent if he buys a book from the distributor at rupees 200 how much does he sell it for so let us first see what is given given our uh profit percent that is 10 percent so we write it as profit percent which is 10 percent and the purse book seller buys from the distributor at rupees 200 that means cost price of the book is rupees 200 now what do we need to find out to find how much does he sell it for so we need to find the selling price okay so let us solve it so what is the formula for profit percentage profit percent is equal to profit by cost price in 200 now profit percent is given that is 10 percent so we write it as 10 percent is equal to profit is not given so we just write it as p cost price is 200 so we write it as 200 in 200 so now we can further simplify it and you get it as 10 is equal to p by 2. so let us draw a line over here in between to continue solving okay so therefore p is equal to we take 2 on the other side and you get 10 into 2 is equal to 20 rupees so profit you got got it as 20 rupees so now you can easily calculate selling price therefore selling price is equal to profit plus cost price right whenever selling price is greater than cost price so we are not aware of it whether it's crater or not but we know the profit amounts so we are sure that there is a profit so just put 20 rupees here plus cost price which is 200 so that gives you answer selling price of the book is 220 rupees okay so that's it for now thank you so much and for further doubts you can put a comment in the comment section and uh for further updates please subscribe to our channel thank you so much"
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