RD Sharma Solutions Class 7 Mathematics Solutions for Integers Exercise 1.3 in Chapter 1 - Integers

Question 10 Integers Exercise 1.3

3 – (5 – 6 ÷ 3)


Given 3 – (5 – 6 ÷ 3)

According to BODMAS rule we have operate in brackets first then we have move to subtraction.

Therefore 3 – (5 – 6 ÷ 3) = 3 – (5 – 2)

= 3 –3 = 0

Video transcript
"You don't even if you I mean it, I'm your tutor. And today we are going to solve this very easy problem. Yeah. Now again remember Partners, right? You have to remember Partners whenever you're being such problems, but it is the application of one was where students can make mistakes. Okay. So sorry this is bracket. So bracket of division multiplication addition and subtraction. Okay, so we are going to become more efficient in that order. So in our in our expression what we have we have a Graphic so we are going to solve the maggots. I'm gonna take the bracket. We have division subtraction. So we subtract the week before division first. So this will be 3 minus 5 minus 6 divided by 3 is 2 in again 3 minus 5 minus 2 is 3 which will give us 0 a dancer. Okay. So this is very easy Gates. We just have to remember applying the balm us whenever you bring such calculations. If you have any doubts, please leave a comment below and do like the video and do not forget to subscribe to our Channel because we keep coming up with these videos will help you refine your academics take such even on this video Until then bye kids. He practicing NBC"
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