 # RD Sharma Solutions Class 6 Mathematics Solutions for Exercise 16.2 in Chapter 15 - Understanding Three Dimensional Shapes

A gas pipe is an example of a

(a)cone

(b)a cylinder

(c)cube

(d)sphere

The option (b) is the correct answer.

A gas pipe is an example of a cylinder.

Video transcript
"hello student welcome to the leader dog solving session and in today's session we are going to discuss one more question related to mathematics all right so first i am going to read the question so the question is the water for a factory it's still is stored in a hemispherical tank so size of the tank is given here which is hemisphere okay and okay the internal diameter is given here that is 14 meter the tank contain 50 kilo liters of water okay water is pumped into the tank to fill to its capacity right that means we are adding the water okay so that the tank will tank will be filled fully all right so we are going okay calculate the volume of water pumped into the tank all right okay so let's solve this question so according to the given question internal diameter of the tank is given okay so internal [Music] diameter is given here internal diameter for the hemispherical tank internal diameter is close to 14 meter all right and that's why we can find out the internal radius right so internal radius of the tank okay which is equal to 14 upon 2 which is 7 meter all right now as we know that tank contains 50 kilo liter of water right kilo liter of water okay that means it is equal to 50 meter cube of water right because one kilo liter is nothing but one kilo liter is nothing but one meter cube all right okay now what we are going to do we are going to find out the volume okay so volume of the hemisphere formula is viewed okay so volume of hemisphere atmosphere or hemispheric tan which is equal to 2 upon 3 multiplied by pi r q all right okay that means volume of the hemispherical tan okay let's consider it as in b okay or it is v one okay so v one will be two upon three into value of pi is three point one four okay multiplied by okay r is seven meter which we already find find out so it is r two all right which is equals to two upon three multiplied by 3.14 okay say 1 cube is it is 343 all right ok now we place all this so it will be three point one four okay two multiplied by 343 which will gives 680 upon 3 right so further calculating okay the volume of the hemispherical tan will be 700 718.66 meter cube right okay so that is the volume of the hemispherical tank right now as we know that okay 50 meter cube water is already present okay in the tank now what we are going to do we are going to find out the okay volume of pumped water right so that means okay volume [Music] of pumped water from front water is equal to volume of hemispherical tank that is v1 okay minus okay the water which is present in the tank that means is 50 meter cube all right so v1 is 718.66 minus 50 right so that means okay volume of the pumped water which is equal to 7 for 718.66 minus 15 okay which will give us 668 point six six okay it will be meter cube right that means we need to pump 668.66 meter cube water so that the tank will fill completely all right so that's all about today's session if you have any doubt please leave the comment below and please subscribe to this channel thanks for watching our video bye "
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