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RD Sharma Solutions Class 6 Mathematics Solutions for Exercise 16.2 in Chapter 15 - Understanding Three Dimensional Shapes
Prev
A gas pipe is an example of a
(a)cone
(b)a cylinder
(c)cube
(d)sphere
Answer:
The option (b) is the correct answer.
A gas pipe is an example of a cylinder.
Video transcript
"hello student welcome to the leader dog
solving session
and in today's session we are going to
discuss one more question related to
mathematics all right so first i am
going to read the question
so the question is the water
for a factory it's still is stored in a
hemispherical
tank so size of the tank is given here
which is
hemisphere okay and
okay the internal diameter
is given here that is 14 meter
the tank contain 50 kilo liters of water
okay water is pumped into the tank to
fill to its capacity right that means we
are adding the water okay
so that the tank will tank will be
filled fully
all right so we are going okay calculate
the volume
of water pumped into the tank
all right okay so let's
solve this question so
according to the given question
internal diameter of the tank is given
okay
so internal
[Music]
diameter is given here internal diameter
for the hemispherical tank
internal diameter is close to 14 meter
all right and that's why we can find out
the
internal radius right so internal radius
of the tank
okay which is equal to 14 upon 2
which is 7 meter
all right now as we know that
tank contains
50 kilo liter of water right
kilo liter of water
okay that means it is equal to
50 meter cube of water right
because
one kilo liter is nothing but
one kilo liter is nothing but
one meter cube
all right okay now what we are going to
do we are going to find out the
volume okay so volume of the hemisphere
formula is viewed okay so volume
of hemisphere
atmosphere or hemispheric tan
which is equal to 2
upon 3 multiplied by
pi r q all right
okay that means volume of the
hemispherical tan
okay let's consider it as in b okay or
it is v one
okay so v one will be
two upon three into value of pi
is three point one four okay
multiplied by okay r is seven meter
which we already find find out so it is
r
two all right which is equals to
two upon three multiplied by 3.14
okay say 1 cube is
it is 343
all right ok now we place all this
so it will be three
point one four okay
two multiplied by 343
which will gives 680
upon 3 right so further calculating
okay the volume of the hemispherical tan
will be
700 718.66
meter cube right
okay so that is the volume of the
hemispherical tank right
now as we know that okay 50
meter cube water is already present okay
in the tank now what we are going to do
we are going to find out the
okay volume of pumped water right
so that means okay volume
[Music]
of pumped water
from front water
is equal to volume of
hemispherical tank that is v1
okay minus
okay the water which is present in the
tank
that means is 50
meter cube all right so
v1 is 718.66
minus
50 right so that means okay volume of
the pumped water which is equal to
7 for 718.66 minus
15 okay which will give us 668
point six six okay
it will be meter cube right
that means we need to pump 668.66
meter cube water so that
the tank will fill completely all right
so that's all about today's session if
you have any doubt
please leave the comment below and
please subscribe to this channel
thanks for watching our video bye
"
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