If the HCF of 657 and 963 is expressible in the form 657x 963 x 15 find x...

Question

If the HCF of 657 and 963 is expressible in the form 657x 963 x 15 find x

Accepted Answer

Firstly the HCF of 657 and 963 is to be found By applying Euclids division lemma we get 963 657 x 1 306 Here the remainder 0 and so we apply Euclids division lemma on divisor 657 and remainder 306 657 306 x 2 45 Now continue applying division lemma till the remainder becomes 0 306 45 x 6 36 Again the remainder 0 45 36 x 1 9 Again the remainder 0 36 9 x 4 0 Now the remainder 0 Hence the last divisor is the HCF of 657 and 963 ie 9 So this HCF is expressed as a linear combination which given as 9 657x 936 15 Solving for x we get 9 657x 14445 9 14445 657x 14454 657x x 14454 657 x 22

RD Sharma Solutions Class 10 Mathematics Solutions for Real Numbers Exercise 1.2 in Chapter 1 - Real Numbers