Find the largest number which divides 615 and 963 leaving the remainder 6 in each case...

Question

Find the largest number which divides 615 and 963 leaving the remainder 6 in each case

Accepted Answer

Firstly the required numbers which on dividing doesnt leave any remainder are to be found This is done by subtracting 6 from both the given numbers So the numbers are 615 6 609 and 963 6 957 Now if the HCF of 609 and 957 is found that will be the required number By applying Euclids division lemma 957 609 x 1 348 609 348 x 1 261 348 216 x 1 87 261 87 x 3 0 HCF 87 Therefore the required number is 87

RD Sharma Solutions Class 10 Mathematics Solutions for Real Numbers Exercise 1.2 in Chapter 1 - Real Numbers